Difference between revisions of "Type Coercion"
m (backticks don't do anything in "`(null)`") |
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Line 5: | Line 5: | ||
<c>null * 3 == #@!$</c> | <c>null * 3 == #@!$</c> | ||
Any statement that begins with `null` is a compiler error, but this may change in the future. | Any statement that begins with `null` is a compiler error, but this may change in the future. | ||
− | + | <c>(null)</c> is okay though. | |
<c>3 * null == 0</c> | <c>3 * null == 0</c> |
Revision as of 02:10, 21 February 2024
WIP
Known type coercion rules:
null * 3 == #@!$
Any statement that begins with `null` is a compiler error, but this may change in the future.
(null)
is okay though.
3 * null == 0
Multiplying by null yields 0.
3 / null == Infinity
In division, null acts a lot like `0`.
3 + "3" == "33"
If an expression contains a string, the entire expression will be coerced into a string.
"3" * 5 == "33333
Multiplying a string by a number will replicate the string.
"1234" / 2 == "12"
Dividing a string by a number will divide the length, then take a substring.
1/0 == "INF" | "Infinity"
All numerical math is done according to standard IEEE floating-point rules, including well-defined behavior for Inf and NaN. However, conversion of Inf and NaN to a string is undefined (implementation-dependent).